Solving 2.17 and 2.18 Using the Principle of Virtual Work

It is possible to solve 2.17 and 2.18 using torques, but since the chapter was about using the virtual work principle, let’s use it.

Let’s consider the ladder from the exercise 2.18 (2.17 uses similar approach) rotating clockwise due to the reactive force of the wall.

Let’s imagine a ladder rotating clockwise under the influence of the reaction force of the wall. As the ladder rotates by a small angle $\delta \theta$ radians, it displaces a distance $s = r$ (by the definition of a radian).

For a small angle $\theta$, it is possible to approximate that any point on ladder moves in a straight line, not in a circular path (see figure below).

This linear movement allows us to compute displacement of each point on the ladder as the following:

${\displaystyle \begin{array}{rl}{\displaystyle \mathrm{\Delta }x}& {\displaystyle =s\sin \theta =\delta \theta \cdot r\cdot \sin \theta }\\ {\displaystyle \mathrm{\Delta }y}& {\displaystyle =s\cos \theta =\delta \theta \cdot r\cdot \cos \theta }\end{array}}$

Now we can calculate the work done by a reactive force of the wall $T$:

${\displaystyle W_T=T(\delta \theta \cdot L\cdot \sin \theta )}$

Changes in potential energies of the weight $W$ and the ladder $\omega$ are:

${\displaystyle \begin{array}{rl}{\displaystyle E_W}& {\displaystyle =(\delta \theta \cdot 0.75L\cdot \cos \theta )\cdot W}\\ {\displaystyle E_{\omega }}& {\displaystyle =(\delta \theta \cdot 0.5L\cdot \cos \theta )\cdot \omega }\end{array}}$

Equating the work done by $T$ to the total change in potential energy yields:

${\displaystyle \begin{array}{rl}{\displaystyle T(\delta \theta \cdot L\cdot \sin \theta )}& {\displaystyle =(\delta \theta \cdot 0.5L\cdot \cos \theta )\cdot \omega }\\ {\displaystyle }& {\displaystyle +(\delta \theta \cdot 0.75L\cdot \cos \theta )\cdot W}\end{array}}$

${\displaystyle T=\mathrm{ctg}\theta (0.5\omega +0.75W)}$

Feynman’s Lectures Exercises 2.16

I spent more time on this exercise than needed because I didn’t notice that the masses are equal. Otherwise, the application of the virtual work principle is straightforward.

The work is done by the gravitation force and the force accelerates the entire system, that is $M = m_1 + m_2 = 2m$.

Let’s use the positive sign the direction of gravity acting on $m_2$.

The work can be calculate as:

${\displaystyle \begin{array}{rl}{\displaystyle W}& {\displaystyle =F\mathrm{\Delta }s}\\ {\displaystyle }& {\displaystyle =Ma\cdot \mathrm{\Delta }s}\\ {\displaystyle }& {\displaystyle =Ma\cdot \mathrm{\Delta }{y}_2}\\ {\displaystyle }& {\displaystyle =2m\cdot \mathrm{\Delta }{y}_2}\end{array}}$

This work is equal to the change of the potential energy in the system as follows:

${\displaystyle \begin{array}{rl}{\displaystyle \mathrm{\Delta }{E}_k}& {\displaystyle =m_2\cdot g\cdot \mathrm{\Delta }{y}_2-m_1\cdot g\cdot \mathrm{\Delta }{y}_1}\\ {\displaystyle }& {\displaystyle =m\cdot g\cdot \mathrm{\Delta }{y}_2-m\cdot g\cdot \mathrm{\Delta }{y}_1}\\ {\displaystyle }& {\displaystyle =m\cdot g\cdot (\mathrm{\Delta }{y}_2-\mathrm{\Delta }{y}_1)}\\ {\displaystyle }& {\displaystyle =m\cdot g\cdot (\mathrm{\Delta }{y}_2-\mathrm{\Delta }{y}_2\cdot \sin \frac{\pi }{4})}\end{array}}$

Thus, we get:

${\displaystyle \begin{array}{rl}{\displaystyle a}& {\displaystyle =g\frac{m-m\cdot \sin \frac{\pi }{4}}{2m}}\\ {\displaystyle }& {\displaystyle =g\frac{(1-\sin \frac{\pi }{4})\cdot m}{2m}}\\ {\displaystyle }& {\displaystyle =g\frac{1-\frac{\sqrt{2}}{2}}{2}}\\ {\displaystyle }& {\displaystyle =\frac{1}{2}(1-\frac{1}{\sqrt{2}})g}\end{array}}$

I finally bought the Feynman Lectures on Physics, something I wanted to do for a very long time. Ever since reading You’re Surely Joking Mr. Feynman. After watching some of his interviews on YouTube and going through a few chapters online, I realized there’s something special about how Feynman explains things. He doesn’t just teach formulas — he teaches understanding. Once you grasp that, you realize what true understanding is. Here are a few quotes from the introduction to the New Millennium edition:

It was like going to church. The lectures were a transformational experience, the experience of a lifetime, probably the most important thing I got from Caltech. I was a biology major but Feynman’s lectures stand out as a high point in my undergraduate experience … though I must admit I couldn’t do the homework at the time and I hardly turned any of it in. I was among the least promising of students in this course, and I never missed a lecture. … I remember and can still feel Feynman’s joy of discovery. … His lectures had an … emotional impact that was probably lost in the printed Lectures.

The book is beautiful. I don’t choose books solely on looks, but when there are different options, it’s better to go for the one you like. I’ve noticed that this works for anything — if I like something that’s part of an activity, I’m more likely to engage with it. So, in that sense, it is rational to choose a book by its cover. One sad thing is the lettering from the original edition has been lost in the New Millennium version:

Almost all other popular physics books look very average. Compare another popular textbook with the austere design of Feynman’s lectures:

My plan is to work through all three volumes over the winter and solve all the exercises from the companion workbook. I will buy a refresher for math once I hit a wall. There are a few books I have in mind: Spivak’s Calculus and The Princeton Companion to Applied Mathematics. Both are as beautifully designed as Feynman’s lectures.

Feynman’s Lectures Exercises 2.14 and 2.15

If the weights $W_1$ and $W_2$ move the distance $s$ along the plane to the left, their corresponding difference in height are:

${\displaystyle \mathrm{\Delta }{h}_1=s\cdot \sin \theta ,\mathrm{\Delta }{h}_2=-s\cdot \sin \theta }$

Then, the difference in potential energy of the system is:

${\displaystyle \mathrm{\Delta }{E}_p=\mathrm{\Delta }{h}_1{W}_1-\mathrm{\Delta }{h}_2{W}_2}$

By the definition of work:

${\displaystyle F\cdot s=\mathrm{\Delta }{E}_p}$

Then:

${\displaystyle \begin{array}{rl}{\displaystyle F}& {\displaystyle =\frac{\mathrm{\Delta }{E}_p}{s}}\\ {\displaystyle }& {\displaystyle =\sin \theta \cdot m_1\cdot g-\sin \theta \cdot m_2\cdot g}\\ {\displaystyle }& {\displaystyle =\sin \theta \cdot g\cdot (m_1-m_2)}\end{array}}$

For the acceleration along the plane, using $a =$ and the total mass $m = m_1 + m_2$, the acceleration is:

${\displaystyle a=\sin \theta \cdot g\cdot \frac{m_1-m_2}{m_1+m_2}}$

For the motion over distance $D$, starting from rest:

${\displaystyle D=\frac{a{t}^2}{2}}$

Thus:

${\displaystyle \begin{array}{rl}{\displaystyle t^2}& {\displaystyle =\frac{2D}{a}}\\ {\displaystyle t}& {\displaystyle =\sqrt{\frac{2D}{a}}}\end{array}}$

The speed at time $t$ is given by:

${\displaystyle \begin{array}{rl}{\displaystyle v}& {\displaystyle =at}\\ {\displaystyle }& {\displaystyle =a\cdot \sqrt{\frac{2D}{a}}}\\ {\displaystyle }& {\displaystyle =\sqrt{2Da}}\\ {\displaystyle }& {\displaystyle =\sqrt{2D\cdot \sin \theta \cdot g\cdot \frac{m_1-m_2}{m_1+m_2}}}\end{array}}$

For Exercise 2.15, the acceleration is given by:

${\displaystyle a=\frac{1}{2}\cdot g\cdot (\sin \theta -\sin \varphi )}$

Substituting this into the expression for speed, we get:

${\displaystyle v=\sqrt{g\cdot D\cdot (\sin \theta -\sin \varphi )}}$

Tags: design

Made a few changes to the site, and now I can have posts without titles. It gives a sense of freedom, similar to what you might have unconsciously experienced on Twitter. Having a title adds a layer of seriousness to a post.

The Archive layout has changed to accommodate missing titles — now the dates link to posts, and the dates are in ISO format set in tabular figures for proper alignment.

With each iteration, it’s becoming more brutalist, and I like it.

Tags: music

King Creosote

I found King Creosote randomly through some recommendation on YouTube or Spotify — I don’t remember. Diamond Mine is now the first album I bought in a very long time. Then, I found this tender documentary about life in Scotland and loved it.

These albums are so good at grounding you. You might sit in a train or walk through a busy street, and you start forgetting that you’re part of this crowd. You feel as if you’re a bystander, noticing all the small details in people and things around you — everything that makes them special.

Tags: design, projects, typography

Drawing My First Font

I’ve started drawing my first font. It’s the perfect pastime activity — you massage letters until they start looking good. It’s soothing.

There’s no end goal besides drawing something that I could use for my website. This means I don’t need to think about covering all the glyphs — the basic Latin alphabet would be enough. I’m not even using italics here.

It feels weird not to know the scale, for example, what cap height or x-height to choose. Most of the time, it feels like “I don’t know what I’m doing”. But this is a good feeling because I haven’t felt “stupid” for a while. When you design something for the web, you at least keep your knowledge from using HTML and CSS, so you know the scale. Here’s the medium is new.

For now, I want to push as far as I can without thinking about the font metrics and edit the letters later. It means that I will need to do double work, but it allows me to focus on mastering the tool first.